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Sarah,
The emission
spectrum for 2P excitation is typically exactly the same
as for 1P, so I cannot quite imagine what
this formula is about. Perhaps you
could quote the whole formula?
Perhaps you could
also give the full spec of the dye and the filter
you are using since I'm not quite sure what
you are saying here. If you
have a BP 680/160 filter it will pass from
600nm to 760nm which clearly
covers the red and far red.
Guy
From: Confocal Microscopy List on behalf of
Sarah Kefayati
Sent: Wed 22/08/2007 4:12 AM
To:
[hidden email]
Subject: 2-P
specrtum
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Hello all!
recently I have found a formula in a paper to calculate the emission
wavelength of 2-P spectra,which is slightly greater than the excitation
wavelength divided by 2.I'm just wondering it is a valid formula,if so
,I'm using 800 nm wl and 680 nm filter which is not passing less than 600 nm,but
I have good signal in red?!
regards
Sarah
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